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Logical Reasoning · Logical Connectives, Syllogisms and Venn Diagrams

Venn Diagram - Formula, Key Point and Examples

🔵

VENN DIAGRAM\text{VENN DIAGRAM}
🟢 1. BASIC CONCEPT A Venn diagram is a graphical representation of sets using circles or closed curves.
Venn Diagram=Graphical representation of sets \text{Venn Diagram} = \text{Graphical representation of sets}
The important concepts are:
Union,Intersection,Difference,Complement \text{Union},\quad \text{Intersection},\quad \text{Difference},\quad \text{Complement}
🟢 2. SET A set is a collection of well-defined objects. For example:
A={1,2,3,4,5} A=\{1,2,3,4,5\}
The number of elements in set \(A\) is:
n(A)=5 n(A)=5
🟢 3. UNIVERSAL SET The universal set contains all the elements under consideration. It is represented by:
U U
🟢 4. UNION OF TWO SETS The union of sets \(A\) and \(B\) contains all elements belonging to \(A\), \(B\), or both. It is represented by:
A∪B A\cup B
The formula is:
n(A∪B)=n(A)+n(B)−n(A∩B) n(A\cup B) = n(A)+n(B)-n(A\cap B)
🟢 5. INTERSECTION OF TWO SETS The intersection contains the elements common to both sets. It is represented by:
A∩B A\cap B
🟢 6. DIFFERENCE OF SETS The difference \(A-B\) contains elements that belong to \(A\) but not to \(B\).
A−B A-B
Number of elements:
n(A−B)=n(A)−n(A∩B) n(A-B) = n(A)-n(A\cap B)
Similarly:
n(B−A)=n(B)−n(A∩B) n(B-A) = n(B)-n(A\cap B)
🟢 7. COMPLEMENT OF A SET The complement of \(A\) contains all elements of the universal set that are not in \(A\). It is represented by:
A′ A'
or:
Ac A^c
Formula:
n(A′)=n(U)−n(A) n(A') = n(U)-n(A)
🟢 8. TWO-SET VENN DIAGRAM For two sets \(A\) and \(B\), the important regions are:
A only A\text{ only}
B only B\text{ only}
A∩B A\cap B
Neither A nor B \text{Neither }A\text{ nor }B
🟢 9. ONLY A The elements belonging to \(A\) but not to \(B\) are:
A−B A-B
Therefore:
n(A only)=n(A)−n(A∩B) n(A\text{ only}) = n(A)-n(A\cap B)
🟢 10. ONLY B The elements belonging to \(B\) but not to \(A\) are:
B−A B-A
Therefore:
n(B only)=n(B)−n(A∩B) n(B\text{ only}) = n(B)-n(A\cap B)
🟢 11. NEITHER A NOR B Elements belonging to neither \(A\) nor \(B\) are outside the union.
n(Neither)=n(U)−n(A∪B) n(\text{Neither}) = n(U)-n(A\cup B)
Therefore:
n(Neither)=n(U)−n(A)−n(B)+n(A∩B) n(\text{Neither}) = n(U)-n(A)-n(B)+n(A\cap B)
🟢 12. UNION FORMULA For two sets:
n(A∪B)=n(A)+n(B)−n(A∩B) n(A\cup B) = n(A)+n(B)-n(A\cap B)
🔴 IMPORTANT The intersection is subtracted because common elements are counted twice.
Union=First Set+Second Set−Common Elements \text{Union} = \text{First Set} + \text{Second Set} - \text{Common Elements}
🟢 13. FINDING THE INTERSECTION From the union formula:
n(A∩B)=n(A)+n(B)−n(A∪B) n(A\cap B) = n(A)+n(B)-n(A\cup B)
🟢 14. DISJOINT SETS Two sets are disjoint if they have no common elements. Therefore:
A∩B=∅ A\cap B=\varnothing
and:
n(A∩B)=0 n(A\cap B)=0
Hence:
n(A∪B)=n(A)+n(B) n(A\cup B) = n(A)+n(B)
🟢 15. THREE-SET VENN DIAGRAM For three sets \(A\), \(B\), and \(C\), the important regions are:
A only A\text{ only}
B only B\text{ only}
C only C\text{ only}
A∩B only A\cap B\text{ only}
A∩C only A\cap C\text{ only}
B∩C only B\cap C\text{ only}
A∩B∩C A\cap B\cap C
and:
None \text{None}
🟢 16. THREE-SET UNION FORMULA For three sets:
n(A∪B∪C)=n(A)+n(B)+n(C) n(A\cup B\cup C) = n(A)+n(B)+n(C)
−n(A∩B)−n(A∩C)−n(B∩C) -n(A\cap B) -n(A\cap C) -n(B\cap C)
+n(A∩B∩C) +n(A\cap B\cap C)
🔴 IMPORTANT For three sets, the common intersection of all three sets is added once. 🟢 17. ONLY A IN THREE SETS The number belonging only to \(A\) is:
n(A only)=n(A)−n(A∩B)−n(A∩C)+n(A∩B∩C) n(A\text{ only}) = n(A) -n(A\cap B) -n(A\cap C) +n(A\cap B\cap C)
🟢 18. ONLY B IN THREE SETS
n(B only)=n(B)−n(A∩B)−n(B∩C)+n(A∩B∩C) n(B\text{ only}) = n(B) -n(A\cap B) -n(B\cap C) +n(A\cap B\cap C)
🟢 19. ONLY C IN THREE SETS
n(C only)=n(C)−n(A∩C)−n(B∩C)+n(A∩B∩C) n(C\text{ only}) = n(C) -n(A\cap C) -n(B\cap C) +n(A\cap B\cap C)
🟢 20. A AND B ONLY Elements belonging to \(A\) and \(B\), but not \(C\):
n(A∩B only)=n(A∩B)−n(A∩B∩C) n(A\cap B\text{ only}) = n(A\cap B) -n(A\cap B\cap C)
🟢 21. A AND C ONLY
n(A∩C only)=n(A∩C)−n(A∩B∩C) n(A\cap C\text{ only}) = n(A\cap C) -n(A\cap B\cap C)
🟢 22. B AND C ONLY
n(B∩C only)=n(B∩C)−n(A∩B∩C) n(B\cap C\text{ only}) = n(B\cap C) -n(A\cap B\cap C)
🟢 23. ALL THREE SETS Elements belonging to all three sets are represented by:
A∩B∩C A\cap B\cap C
Therefore:
n(All Three)=n(A∩B∩C) n(\text{All Three}) = n(A\cap B\cap C)
🟢 24. NONE OF THE THREE SETS The number of elements belonging to none of the three sets is:
n(None)=n(U)−n(A∪B∪C) n(\text{None}) = n(U)-n(A\cup B\cup C)
🟢 25. AT LEAST ONE "At least one" means belonging to one or more sets. Therefore:
At Least One=A∪B∪C \text{At Least One} = A\cup B\cup C
Hence:
n(At Least One)=n(A∪B∪C) n(\text{At Least One}) = n(A\cup B\cup C)
🟢 26. AT LEAST TWO "At least two" means belonging to two or three sets.
n(At Least Two)=n(A∩B)+n(A∩C)+n(B∩C) n(\text{At Least Two}) = n(A\cap B) +n(A\cap C) +n(B\cap C)
Since the elements belonging to all three sets are counted three times:
n(At Least Two)=n(A∩B)+n(A∩C)+n(B∩C)−2n(A∩B∩C) n(\text{At Least Two}) = n(A\cap B) +n(A\cap C) +n(B\cap C) -2n(A\cap B\cap C)
🟢 27. EXACTLY TWO "Exactly two" means belonging to exactly two sets but not all three.
n(Exactly Two)=n(A∩B)+n(A∩C)+n(B∩C)−3n(A∩B∩C) n(\text{Exactly Two}) = n(A\cap B) +n(A\cap C) +n(B\cap C) -3n(A\cap B\cap C)
🟢 28. EXACTLY ONE "Exactly one" means belonging to only one of the three sets.
n(Exactly One)=n(A only)+n(B only)+n(C only) n(\text{Exactly One}) = n(A\text{ only}) +n(B\text{ only}) +n(C\text{ only})
🟢 29. AT LEAST ONE AND NONE For the universal set:
n(At Least One)+n(None)=n(U) n(\text{At Least One}) + n(\text{None}) = n(U)
Therefore:
n(None)=n(U)−n(At Least One) n(\text{None}) = n(U)-n(\text{At Least One})
🟢 30. IMPORTANT VENN DIAGRAM SYMBOLS
∪=Union \cup = \text{Union}
∩=Intersection \cap = \text{Intersection}
A−B=Difference A-B = \text{Difference}
A′=Complement of A A' = \text{Complement of A}
∅=Empty Set \varnothing = \text{Empty Set}
U=Universal Set U = \text{Universal Set}
🔴 IMPORTANT KEY POINTS
A∪B=Elements in A or B or both A\cup B = \text{Elements in A or B or both}
A∩B=Elements common to A and B A\cap B = \text{Elements common to A and B}
A−B=Elements in A but not in B A-B = \text{Elements in A but not in B}
A′=Elements not in A A' = \text{Elements not in A}
n(A∪B)=n(A)+n(B)−n(A∩B) n(A\cup B) = n(A)+n(B)-n(A\cap B)
n(A only)=n(A)−n(A∩B) n(A\text{ only}) = n(A)-n(A\cap B)
n(B only)=n(B)−n(A∩B) n(B\text{ only}) = n(B)-n(A\cap B)
n(Neither)=n(U)−n(A∪B) n(\text{Neither}) = n(U)-n(A\cup B)
n(A∪B∪C)=n(A)+n(B)+n(C) n(A\cup B\cup C) = n(A)+n(B)+n(C)
−n(A∩B)−n(A∩C)−n(B∩C) -n(A\cap B) -n(A\cap C) -n(B\cap C)
+n(A∩B∩C) +n(A\cap B\cap C)
At Least One=A∪B∪C \text{At Least One} = A\cup B\cup C
None=U−(A∪B∪C) \text{None} = U-(A\cup B\cup C)
Exactly Two=Pairwise Intersections−3×Triple Intersection \text{Exactly Two} = \text{Pairwise Intersections} - 3\times\text{Triple Intersection}
Always subtract overlapping regions when calculating a union \text{Always subtract overlapping regions when calculating a union}
For three sets, add the triple intersection once \text{For three sets, add the triple intersection once}

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Logical Reasoning · Data Interpretation and Data Sufficiency

Data Sufficiency - Formulas, Key Points and Examples

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DATA SUFFICIENCY\text{DATA SUFFICIENCY}
🟢 1. BASIC CONCEPT Data Sufficiency questions test whether the given information is sufficient to answer a question. The objective is not always to find the answer. The objective is to determine whether the given statements provide enough information to find a unique answer.
Data Sufficiency=Checking whether the given data is sufficient to answer the question \text{Data Sufficiency} = \text{Checking whether the given data is sufficient to answer the question}
🟡 KEY POINT
Sufficient Data≠Necessarily Calculating the Final Answer \text{Sufficient Data}\neq\text{Necessarily Calculating the Final Answer}
🟢 2. STATEMENT-BASED DATA SUFFICIENCY A typical question contains:
Question+Statement I+Statement II \text{Question}+\text{Statement I}+\text{Statement II}
You must determine whether:
Statement I alone is sufficient \text{Statement I alone is sufficient}
or:
Statement II alone is sufficient \text{Statement II alone is sufficient}
or:
Both statements together are sufficient \text{Both statements together are sufficient}
or:
Even both statements together are insufficient \text{Even both statements together are insufficient}
🟢 3. MAIN RULE Always test the statements separately first.
Step 1: Test Statement I alone \text{Step 1: Test Statement I alone}
Step 2: Test Statement II alone \text{Step 2: Test Statement II alone}
Step 3: If neither is sufficient, test Statements I and II together \text{Step 3: If neither is sufficient, test Statements I and II together}
🟡 KEY POINT
Do not combine the statements immediately \text{Do not combine the statements immediately}
🟢 4. STATEMENT I ALONE If Statement I gives enough information to determine a unique answer:
Statement I alone is sufficient \text{Statement I alone is sufficient}
There is no need to use Statement II. 🟢 5. STATEMENT II ALONE If Statement II gives enough information to determine a unique answer:
Statement II alone is sufficient \text{Statement II alone is sufficient}
There is no need to use Statement I. 🟢 6. BOTH STATEMENTS TOGETHER Sometimes neither statement is sufficient individually, but both together provide enough information.
Statement I alone=Insufficient \text{Statement I alone}=\text{Insufficient}
Statement II alone=Insufficient \text{Statement II alone}=\text{Insufficient}
But:
Statement I+Statement II=Sufficient \text{Statement I}+\text{Statement II}=\text{Sufficient}
🟢 7. BOTH STATEMENTS TOGETHER ARE INSUFFICIENT If even after combining both statements, more than one possible answer remains:
Statement I+Statement II=Insufficient \text{Statement I}+\text{Statement II}=\text{Insufficient}
🟡 KEY POINT
Multiple Possible Answers⇒Insufficient Data \text{Multiple Possible Answers}\Rightarrow\text{Insufficient Data}
🟢 8. UNIQUE ANSWER Data is sufficient only when the information leads to one definite answer. If:
x=10 x=10
then the value of \(x\) is uniquely determined. Therefore:
Sufficient \text{Sufficient}
But if:
x>5 x>5
then many values are possible. Therefore:
Insufficient \text{Insufficient}
🟢 9. YES OR NO QUESTIONS For questions asking whether a statement is true or false, the data is sufficient if the statement can be definitely answered with:
YES \text{YES}
or:
NO \text{NO}
If both possibilities remain:
YES or NO \text{YES or NO}
then:
Insufficient \text{Insufficient}
🟢 10. VALUE-BASED QUESTIONS Suppose the question asks:
What is the value of x? \text{What is the value of }x?
The data is sufficient only if \(x\) can be uniquely determined. For example:
x+5=12 x+5=12
Therefore:
x=7 x=7
Hence:
Sufficient \text{Sufficient}
🟢 11. AGE PROBLEMS For age questions, identify the number of unknown ages and the relationships between them. For example:
A+B=40 A+B=40
This alone does not determine \(A\) and \(B\) individually. Therefore:
Insufficient \text{Insufficient}
If another independent equation is given:
A−B=10 A-B=10
then:
A+B=40 A+B=40
A−B=10 A-B=10
Adding both equations:
2A=50 2A=50
A=25 A=25
Therefore:
B=15 B=15
Hence:
Sufficient \text{Sufficient}
🟢 12. NUMBER PROBLEMS If the question asks for the value of a number and a statement gives:
x=25 x=25
then:
Statement is Sufficient \text{Statement is Sufficient}
But if the statement only gives:
x>10 x>10
then:
Statement is Insufficient \text{Statement is Insufficient}
🟢 13. EQUATION-BASED SUFFICIENCY One equation with two unknowns is generally insufficient. For example:
x+y=20 x+y=20
There are many possible values of \(x\) and \(y\). Therefore:
Insufficient \text{Insufficient}
Two independent equations may be sufficient:
x+y=20 x+y=20
x−y=4 x-y=4
Adding the equations:
2x=24 2x=24
x=12 x=12
Therefore:
y=8 y=8
Hence:
Sufficient \text{Sufficient}
🟢 14. INEQUALITY An inequality may or may not provide a unique answer. For example:
x>10 x>10
does not determine a unique value. Therefore:
Insufficient \text{Insufficient}
But if the question asks whether \(x\) is positive:
x>10 x>10
then:
x>0 x>0
Therefore:
Sufficient \text{Sufficient}
🟢 15. RATIO PROBLEMS A ratio alone may be insufficient if the actual values are required. For example:
A:B=2:3 A:B=2:3
The actual values could be:
A=2,B=3 A=2,\quad B=3
or:
A=4,B=6 A=4,\quad B=6
or:
A=20,B=30 A=20,\quad B=30
Therefore, the actual values cannot be uniquely determined.
Insufficient \text{Insufficient}
🟢 16. RATIO WITH TOTAL If:
A:B=2:3 A:B=2:3
and:
A+B=50 A+B=50
then:
2x+3x=50 2x+3x=50
5x=50 5x=50
x=10 x=10
Therefore:
A=20 A=20
B=30 B=30
Hence:
Sufficient \text{Sufficient}
🟢 17. PERCENTAGE PROBLEMS If the question asks for a percentage and the required part and whole are known:
Percentage=PartWhole×100 \text{Percentage} = \frac{\text{Part}}{\text{Whole}}\times100
If both the part and whole can be determined:
Sufficient \text{Sufficient}
If either the part or whole cannot be determined:
Insufficient \text{Insufficient}
🟢 18. AVERAGE PROBLEMS If the number of observations and total are known:
Average=TotalNumber of Observations \text{Average} = \frac{\text{Total}}{\text{Number of Observations}}
Therefore:
Total+Number of Observations⇒Sufficient \text{Total}+\text{Number of Observations} \Rightarrow\text{Sufficient}
If only the average is known and the total is required, the data is generally insufficient unless the number of observations is also known. 🟢 19. GEOMETRY PROBLEMS For geometry questions, determine whether the given information uniquely fixes the required quantity. For a rectangle:
Area=l×b \text{Area}=l\times b
If both length and breadth are known:
l,b⇒Area l,\quad b\Rightarrow\text{Area}
Hence:
Sufficient \text{Sufficient}
🟢 20. TRIANGLE PROBLEMS The sum of the angles of a triangle is:
A+B+C=180∘ A+B+C=180^\circ
If two angles are known, the third angle can be determined. For example:
A=60∘ A=60^\circ
B=70∘ B=70^\circ
Therefore:
C=180∘−60∘−70∘ C=180^\circ-60^\circ-70^\circ
C=50∘ C=50^\circ
Hence:
Sufficient \text{Sufficient}
🟢 21. SPEED, TIME AND DISTANCE The basic relationship is:
Distance=Speed×Time \text{Distance} = \text{Speed}\times\text{Time}
Therefore:
d=st d=st
If speed and time are known:
s,t⇒d s,\quad t\Rightarrow d
Hence:
Sufficient \text{Sufficient}
🟢 22. TIME AND WORK The basic relationship is:
Work=Rate×Time \text{Work} = \text{Rate}\times\text{Time}
If the rate and time are known:
W=RT W=RT
Therefore:
R,T⇒W R,\quad T\Rightarrow W
Hence:
Sufficient \text{Sufficient}
🟢 23. PROFIT AND LOSS The basic relationships are:
Profit=SP−CP \text{Profit}=SP-CP
and:
Loss=CP−SP \text{Loss}=CP-SP
To determine profit or loss, the required values must be known or uniquely derivable. 🟡 KEY POINT
Do Not Assume a Missing Value \text{Do Not Assume a Missing Value}
🟢 24. DATA SUFFICIENCY VS DATA INTERPRETATION Data Interpretation asks you to calculate or interpret information.
Data Interpretation→Find the Answer \text{Data Interpretation}\rightarrow\text{Find the Answer}
Data Sufficiency asks whether the information is enough.
Data Sufficiency→Check Whether the Answer Can Be Determined \text{Data Sufficiency}\rightarrow\text{Check Whether the Answer Can Be Determined}
🟢 25. DO NOT USE UNNECESSARY INFORMATION A statement may contain information that is not required. The important question is:
Can the Required Answer Be Uniquely Determined? \text{Can the Required Answer Be Uniquely Determined?}
If yes:
Sufficient \text{Sufficient}
If no:
Insufficient \text{Insufficient}
🟢 26. INDEPENDENT INFORMATION Two statements are useful together when they provide independent information. For example:
x+y=20 x+y=20
and:
x−y=4 x-y=4
These are independent equations and determine \(x\) and \(y\). Therefore:
Together They Are Sufficient \text{Together They Are Sufficient}
🟢 27. REDUNDANT INFORMATION Sometimes both statements provide essentially the same information. For example:
x=10 x=10
and:
2x=20 2x=20
Statement I alone is sufficient. Statement II alone is also sufficient. Therefore:
Either Statement Alone Is Sufficient \text{Either Statement Alone Is Sufficient}
🟢 28. COMMON ANSWER PATTERN Many aptitude tests use answer choices such as:
A. Statement I alone is sufficient \text{A. Statement I alone is sufficient}
B. Statement II alone is sufficient \text{B. Statement II alone is sufficient}
C. Both statements together are sufficient \text{C. Both statements together are sufficient}
D. Either statement alone is sufficient \text{D. Either statement alone is sufficient}
E. Even both statements together are insufficient \text{E. Even both statements together are insufficient}
🟡 KEY POINT
Follow the Exact Answer-Choice Convention Given in the Examination \text{Follow the Exact Answer-Choice Convention Given in the Examination}
🔴 IMPORTANT KEY POINTS
Test Statement I Alone First \text{Test Statement I Alone First}
Test Statement II Alone Next \text{Test Statement II Alone Next}
Combine Them Only When Necessary \text{Combine Them Only When Necessary}
Sufficient Means a Unique Answer Can Be Determined \text{Sufficient Means a Unique Answer Can Be Determined}
More Than One Possible Answer Means Insufficient \text{More Than One Possible Answer Means Insufficient}
Do Not Assume Information That Is Not Given \text{Do Not Assume Information That Is Not Given}
Do Not Solve More Than Necessary \text{Do Not Solve More Than Necessary}
A Statement Can Be Sufficient Even If the Actual Answer Is Not Calculated \text{A Statement Can Be Sufficient Even If the Actual Answer Is Not Calculated}
For YES/NO Questions, One Definite Answer Is Sufficient \text{For YES/NO Questions, One Definite Answer Is Sufficient}
Check Each Statement Independently Before Combining Them \text{Check Each Statement Independently Before Combining Them}

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Logical Reasoning · Data Interpretation and Data Sufficiency

Data Interpretation - Formulas, Key Points and Examples

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DATA INTERPRETATION\text{DATA INTERPRETATION}
🟢 1. BASIC CONCEPT Data Interpretation means analyzing given data and using it to calculate required values. Data may be presented in the form of:
Tables \text{Tables}
Bar Graphs \text{Bar Graphs}
Line Graphs \text{Line Graphs}
Pie Charts \text{Pie Charts}
Mixed Graphs \text{Mixed Graphs}
🟡 KEY POINT
Read the data carefully before performing any calculation. \text{Read the data carefully before performing any calculation.}
🟢 2. DATA TABLE A table presents information in rows and columns. For example:
Total=Sum of all relevant values \text{Total} = \text{Sum of all relevant values}
If values are:
a, b, c, d a,\ b,\ c,\ d
then:
Total=a+b+c+d \text{Total}=a+b+c+d
🟢 3. TOTAL VALUE To find the total of different categories:
Total=Value1+Value2+Value3+⋯ \text{Total} = \text{Value}_1+\text{Value}_2+\text{Value}_3+\cdots
🟡 KEY POINT
Always include all categories specified in the question. \text{Always include all categories specified in the question.}
🟢 4. DIFFERENCE The difference between two values is:
Difference=Larger Value−Smaller Value \text{Difference} = \text{Larger Value}-\text{Smaller Value}
For two quantities A and B:
Difference=∣A−B∣ \text{Difference}=|A-B|
🟢 5. RATIO To find the ratio of A to B:
Ratio=A:B \text{Ratio} = A:B
or:
Ratio=AB \text{Ratio} = \frac{A}{B}
The ratio should be simplified whenever possible. 🟢 6. PERCENTAGE To find what percentage A is of B:
Percentage=AB×100 \text{Percentage} = \frac{A}{B}\times100
🟡 KEY POINT
The denominator must be the reference value mentioned in the question. \text{The denominator must be the reference value mentioned in the question.}
🟢 7. PERCENTAGE INCREASE If a value changes from an original value to a new value:
Increase=New Value−Original Value \text{Increase} = \text{New Value}-\text{Original Value}
Percentage Increase=IncreaseOriginal Value×100 \text{Percentage Increase} = \frac{\text{Increase}}{\text{Original Value}}\times100
🟢 8. PERCENTAGE DECREASE
Decrease=Original Value−New Value \text{Decrease} = \text{Original Value}-\text{New Value}
Percentage Decrease=DecreaseOriginal Value×100 \text{Percentage Decrease} = \frac{\text{Decrease}}{\text{Original Value}}\times100
🟢 9. AVERAGE The average of a set of values is:
Average=Sum of ValuesNumber of Values \text{Average} = \frac{\text{Sum of Values}}{\text{Number of Values}}
For n values:
Average=x1+x2+x3+⋯+xnn \text{Average} = \frac{x_1+x_2+x_3+\cdots+x_n}{n}
🟢 10. WEIGHTED AVERAGE When different values have different frequencies or weights:
Weighted Average=∑wx∑w \text{Weighted Average} = \frac{\sum wx}{\sum w}
where:
w=Weight w=\text{Weight}
and:
x=Value x=\text{Value}
🟢 11. BAR GRAPH A bar graph represents data using rectangular bars. The length or height of each bar represents the corresponding value.
Bar Length∝Data Value \text{Bar Length}\propto\text{Data Value}
🟡 KEY POINT
Check the scale before reading the value from a bar graph. \text{Check the scale before reading the value from a bar graph.}
🟢 12. BAR GRAPH SCALE If one division represents k units:
Value=Number of Divisions×k \text{Value} = \text{Number of Divisions}\times k
For example, if one division represents 20:
5 divisions=5×20 5\text{ divisions}=5\times20
=100 =100
🟢 13. DOUBLE BAR GRAPH A double bar graph compares two sets of data. For categories A, B and C:
Difference=First Data Set−Second Data Set \text{Difference} = \text{First Data Set}-\text{Second Data Set}
The values should be compared category by category. 🟢 14. LINE GRAPH A line graph shows changes in data over time or across different categories. The change between two consecutive values is:
Change=New Value−Previous Value \text{Change} = \text{New Value}-\text{Previous Value}
🟡 KEY POINT
Look at the direction and scale of the line carefully. \text{Look at the direction and scale of the line carefully.}
🟢 15. TOTAL FROM A LINE GRAPH If the values shown are:
x1,x2,x3,…,xn x_1,x_2,x_3,\ldots,x_n
then:
Total=x1+x2+x3+⋯+xn \text{Total} = x_1+x_2+x_3+\cdots+x_n
🟢 16. PIE CHART A pie chart represents a whole as a circle of:
360∘ 360^\circ
The complete data represents:
100% 100\%
Therefore:
360∘=100% 360^\circ=100\%
🟢 17. PIE CHART ANGLE TO VALUE If the total quantity is T and the sector angle is θ:
Value=θ360∘×T \text{Value} = \frac{\theta}{360^\circ}\times T
🟢 18. PIE CHART VALUE TO ANGLE If a category has value V and the total is T:
Angle=VT×360∘ \text{Angle} = \frac{V}{T}\times360^\circ
🟢 19. PIE CHART ANGLE TO PERCENTAGE
Percentage=θ360∘×100 \text{Percentage} = \frac{\theta}{360^\circ}\times100
🟢 20. PIE CHART PERCENTAGE TO ANGLE
Angle=Percentage100×360∘ \text{Angle} = \frac{\text{Percentage}}{100}\times360^\circ
Therefore:
Angle=Percentage×3.6∘ \text{Angle} = \text{Percentage}\times3.6^\circ
🟢 21. IMPORTANT PIE CHART VALUES For 50%:
50%→180∘ 50\%\rightarrow180^\circ
For 25%:
25%→90∘ 25\%\rightarrow90^\circ
For 20%:
20%→72∘ 20\%\rightarrow72^\circ
For 10%:
10%→36∘ 10\%\rightarrow36^\circ
For 5%:
5%→18∘ 5\%\rightarrow18^\circ
🟢 22. FINDING TOTAL FROM A PIE CHART If a sector represents V and has angle θ:
V=θ360∘×T V = \frac{\theta}{360^\circ}\times T
Therefore:
T=V×360∘θ T = \frac{V\times360^\circ}{\theta}
🟢 23. COMPARISON OF TWO VALUES To find how many times A is B:
Times=AB \text{Times} = \frac{A}{B}
To find how much greater A is than B:
Difference=A−B \text{Difference} = A-B
To find the percentage by which A is greater than B:
Percentage=A−BB×100 \text{Percentage} = \frac{A-B}{B}\times100
🟢 24. RATIO OF TWO CATEGORIES If two categories have values A and B:
Ratio=A:B \text{Ratio}=A:B
If the ratio must be simplified, divide both terms by their HCF.\text{If the ratio must be simplified, divide both terms by their HCF.}
🟢 25. FINDING UNKNOWN VALUE If the total and known values are given:
Unknown=Total−Sum of Known Values \text{Unknown} = \text{Total}-\text{Sum of Known Values}
🟢 26. TOTAL FROM PERCENTAGES If a total T is divided into percentages:
p1%,p2%,p3%,… p_1\%,p_2\%,p_3\%,\ldots
then the corresponding values are:
Value=p100×T \text{Value} = \frac{p}{100}\times T
🟢 27. FINDING PERCENTAGE FROM A TABLE If a category has value A and the total is T:
Percentage=AT×100 \text{Percentage} = \frac{A}{T}\times100
🟢 28. FINDING AVERAGE FROM A TABLE If the values are:
x1,x2,x3,…,xn x_1,x_2,x_3,\ldots,x_n
then:
Average=x1+x2+x3+⋯+xnn \text{Average} = \frac{x_1+x_2+x_3+\cdots+x_n}{n}
🟢 29. AVERAGE WHEN TOTAL IS GIVEN If the total of n observations is T:
Average=Tn \text{Average} = \frac{T}{n}
Therefore:
T=Average×n T=\text{Average}\times n
🟢 30. CHANGE IN AVERAGE If the total changes by ΔT while the number of observations remains n:
Change in Average=ΔTn \text{Change in Average} = \frac{\Delta T}{n}
🟢 31. MISSING VALUE USING AVERAGE If n values have an average A:
Total=nA \text{Total} = nA
If the sum of known values is S:
Missing Value=nA−S \text{Missing Value} = nA-S
🟢 32. COMBINED DATA If two groups have totals T₁ and T₂ and numbers of observations n₁ and n₂:
Combined Average=T1+T2n1+n2 \text{Combined Average} = \frac{T_1+T_2}{n_1+n_2}
Using individual averages A₁ and A₂:
Combined Average=n1A1+n2A2n1+n2 \text{Combined Average} = \frac{n_1A_1+n_2A_2}{n_1+n_2}
🟢 33. PERCENTAGE OF TOTAL If a category has value V and total value is T:
Percentage Share=VT×100 \text{Percentage Share} = \frac{V}{T}\times100
🟢 34. TOTAL PRODUCTION OR SALES If production or sales are given for different years:
Total=Year 1+Year 2+Year 3+⋯ \text{Total} = \text{Year 1}+\text{Year 2}+\text{Year 3}+\cdots
🟢 35. YEAR-TO-YEAR CHANGE For two consecutive years:
Change=Current Year Value−Previous Year Value \text{Change} = \text{Current Year Value}-\text{Previous Year Value}
Percentage change:
Percentage Change=ChangePrevious Year Value×100 \text{Percentage Change} = \frac{\text{Change}}{\text{Previous Year Value}}\times100
🟢 36. DATA SUFFICIENCY IN DI Some questions provide multiple statements or pieces of data. The objective is to determine whether the given information is sufficient to answer the question. 🟡 KEY POINT
Do not calculate unnecessary values. \text{Do not calculate unnecessary values.}
Use only the information required to answer the question. 🟢 37. APPROXIMATION Approximation can be used when the question asks for an approximate value. For example:
49.8≈50 49.8\approx50
99.7≈100 99.7\approx100
🟡 KEY POINT
Use approximation only when the question permits an approximate answer. \text{Use approximation only when the question permits an approximate answer.}
🟢 38. UNIT CONVERSION Always make sure that quantities use the same units before comparing or calculating. For example:
1 km=1000 m 1\text{ km}=1000\text{ m}
1 hour=60 minutes 1\text{ hour}=60\text{ minutes}
1 kg=1000 g 1\text{ kg}=1000\text{ g}
🟢 39. IMPORTANT DI SHORTCUT If a value is increased by x%:
New Value=Old Value(1+x100) \text{New Value} = \text{Old Value}\left(1+\frac{x}{100}\right)
If a value is decreased by x%:
New Value=Old Value(1−x100) \text{New Value} = \text{Old Value}\left(1-\frac{x}{100}\right)
🟢 40. SUCCESSIVE CHANGES If a value changes successively by a% and b%:
Net Change=(a+b+ab100)% \text{Net Change} = \left(a+b+\frac{ab}{100}\right)\%
when both changes are increases. For two decreases:
Net Decrease=(a+b−ab100)% \text{Net Decrease} = \left(a+b-\frac{ab}{100}\right)\%
🔴 IMPORTANT KEY POINTS
Read the title and headings before solving. \text{Read the title and headings before solving.}
Check the units carefully. \text{Check the units carefully.}
Check the scale of graphs. \text{Check the scale of graphs.}
Identify the total before calculating percentages. \text{Identify the total before calculating percentages.}
For percentage, use the correct reference value as the denominator. \text{For percentage, use the correct reference value as the denominator.}
For pie charts, remember 360∘=100%. \text{For pie charts, remember }360^\circ=100\%.
For averages, Average=TotalNumber of Observations. \text{For averages, Average}=\frac{\text{Total}}{\text{Number of Observations}}.
For ratios, simplify the final ratio whenever possible. \text{For ratios, simplify the final ratio whenever possible.}
For differences, subtract the smaller value from the larger value. \text{For differences, subtract the smaller value from the larger value.}
For percentage increase or decrease, compare with the original value. \text{For percentage increase or decrease, compare with the original value.}
Do not confuse total value with average value. \text{Do not confuse total value with average value.}
Use only the data required by the question. \text{Use only the data required by the question.}
Check the final answer against the given data. \text{Check the final answer against the given data.}

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Logical Reasoning · Data Arrangements and Blood Relations

Blood Relations

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BLOOD RELATIONS\text{BLOOD RELATIONS}
🟢 1. BASIC BLOOD RELATIONSHIP Blood relation questions involve identifying the relationship between two people using family connections.
Blood Relation=Relationship between two members of a family \text{Blood Relation} = \text{Relationship between two members of a family}
Common relationships include:
Father, Mother, Son, Daughter, Brother, Sister \text{Father,\ Mother,\ Son,\ Daughter,\ Brother,\ Sister}
Grandfather, Grandmother, Grandson, Granddaughter \text{Grandfather,\ Grandmother,\ Grandson,\ Granddaughter}
Uncle, Aunt, Nephew, Niece \text{Uncle,\ Aunt,\ Nephew,\ Niece}
Cousin \text{Cousin}
🟡 KEY POINT
Always start from the person mentioned in the question and trace the relationship step by step. \text{Always start from the person mentioned in the question and trace the relationship step by step.}
🟢 2. IMMEDIATE FAMILY RELATIONS Father:
Father=Male parent \text{Father}=\text{Male parent}
Mother:
Mother=Female parent \text{Mother}=\text{Female parent}
Son:
Son=Male child \text{Son}=\text{Male child}
Daughter:
Daughter=Female child \text{Daughter}=\text{Female child}
Brother:
Brother=Male sibling \text{Brother}=\text{Male sibling}
Sister:
Sister=Female sibling \text{Sister}=\text{Female sibling}
🟢 3. PARENT-CHILD RELATIONSHIP If A is the father of B:
A→B A\rightarrow B
If A is the mother of B:
A→B A\rightarrow B
If A is the son of B:
B→A B\rightarrow A
If A is the daughter of B:
B→A B\rightarrow A
🟡 KEY POINT
Parent is one generation above the child. \text{Parent is one generation above the child.}
🟢 4. SIBLING RELATIONSHIP A brother and sister share at least one parent. If A and B have the same parents:
A↔B A\leftrightarrow B
If A is male:
A=Brother A=\text{Brother}
If A is female:
A=Sister A=\text{Sister}
🟡 KEY POINT
Brothers and sisters belong to the same generation. \text{Brothers and sisters belong to the same generation.}
🟢 5. GRANDFATHER AND GRANDMOTHER A grandfather is the father of one's parent.
Grandfather=Father of Father or Father of Mother \text{Grandfather} = \text{Father of Father or Father of Mother}
A grandmother is the mother of one's parent.
Grandmother=Mother of Father or Mother of Mother \text{Grandmother} = \text{Mother of Father or Mother of Mother}
🟢 6. GRANDCHILDREN A grandson is the son of one's child.
Grandson=Son of Son or Son of Daughter \text{Grandson} = \text{Son of Son or Son of Daughter}
A granddaughter is the daughter of one's child.
Granddaughter=Daughter of Son or Daughter of Daughter \text{Granddaughter} = \text{Daughter of Son or Daughter of Daughter}
🟢 7. UNCLE An uncle is generally the brother of one's parent.
Uncle=Brother of Father or Brother of Mother \text{Uncle} = \text{Brother of Father or Brother of Mother}
In some family structures, the husband of an aunt may also be referred to as an uncle. 🟡 KEY POINT
Trace through the parent first when identifying an uncle. \text{Trace through the parent first when identifying an uncle.}
🟢 8. AUNT An aunt is generally the sister of one's parent.
Aunt=Sister of Father or Sister of Mother \text{Aunt} = \text{Sister of Father or Sister of Mother}
The wife of an uncle may also be referred to as an aunt. 🟢 9. NEPHEW A nephew is the son of one's brother or sister.
Nephew=Son of Brother or Son of Sister \text{Nephew} = \text{Son of Brother or Son of Sister}
🟢 10. NIECE A niece is the daughter of one's brother or sister.
Niece=Daughter of Brother or Daughter of Sister \text{Niece} = \text{Daughter of Brother or Daughter of Sister}
🟢 11. COUSIN A cousin is generally the child of one's uncle or aunt.
Cousin=Child of Uncle or Aunt \text{Cousin} = \text{Child of Uncle or Aunt}
A male cousin is:
Male Cousin \text{Male Cousin}
A female cousin is:
Female Cousin \text{Female Cousin}
🟢 12. PATERNAL RELATIONS Paternal relationships are related through the father. Father's father:
Paternal Grandfather \text{Paternal Grandfather}
Father's mother:
Paternal Grandmother \text{Paternal Grandmother}
Father's brother:
Paternal Uncle \text{Paternal Uncle}
Father's sister:
Paternal Aunt \text{Paternal Aunt}
🟡 KEY POINT
Paternal means related through the father. \text{Paternal means related through the father.}
🟢 13. MATERNAL RELATIONS Maternal relationships are related through the mother. Mother's father:
Maternal Grandfather \text{Maternal Grandfather}
Mother's mother:
Maternal Grandmother \text{Maternal Grandmother}
Mother's brother:
Maternal Uncle \text{Maternal Uncle}
Mother's sister:
Maternal Aunt \text{Maternal Aunt}
🟡 KEY POINT
Maternal means related through the mother. \text{Maternal means related through the mother.}
🟢 14. BROTHER'S SON The son of one's brother is:
Brother’s Son=Nephew \text{Brother's Son} = \text{Nephew}
🟢 15. BROTHER'S DAUGHTER The daughter of one's brother is:
Brother’s Daughter=Niece \text{Brother's Daughter} = \text{Niece}
🟢 16. SISTER'S SON The son of one's sister is:
Sister’s Son=Nephew \text{Sister's Son} = \text{Nephew}
🟢 17. SISTER'S DAUGHTER The daughter of one's sister is:
Sister’s Daughter=Niece \text{Sister's Daughter} = \text{Niece}
🟢 18. FATHER'S BROTHER The brother of one's father is:
Father’s Brother=Uncle \text{Father's Brother} = \text{Uncle}
🟢 19. FATHER'S SISTER The sister of one's father is:
Father’s Sister=Aunt \text{Father's Sister} = \text{Aunt}
🟢 20. MOTHER'S BROTHER The brother of one's mother is:
Mother’s Brother=Maternal Uncle \text{Mother's Brother} = \text{Maternal Uncle}
🟢 21. MOTHER'S SISTER The sister of one's mother is:
Mother’s Sister=Maternal Aunt \text{Mother's Sister} = \text{Maternal Aunt}
🟢 22. FATHER'S FATHER The father of one's father is:
Father’s Father=Grandfather \text{Father's Father} = \text{Grandfather}
More specifically:
Father’s Father=Paternal Grandfather \text{Father's Father} = \text{Paternal Grandfather}
🟢 23. MOTHER'S FATHER The father of one's mother is:
Mother’s Father=Maternal Grandfather \text{Mother's Father} = \text{Maternal Grandfather}
🟢 24. FATHER'S MOTHER The mother of one's father is:
Father’s Mother=Paternal Grandmother \text{Father's Mother} = \text{Paternal Grandmother}
🟢 25. MOTHER'S MOTHER The mother of one's mother is:
Mother’s Mother=Maternal Grandmother \text{Mother's Mother} = \text{Maternal Grandmother}
🟢 26. GENERATION LEVELS Family relationships can be understood using generations. Parents are:
+1 generation +1\text{ generation}
Children are:
−1 generation -1\text{ generation}
Grandparents are:
+2 generations +2\text{ generations}
Grandchildren are:
−2 generations -2\text{ generations}
Siblings are:
0 generation difference 0\text{ generation difference}
🟡 KEY POINT
Use generation levels to simplify complicated family relationships. \text{Use generation levels to simplify complicated family relationships.}
🟢 27. FAMILY TREE A family tree represents relationships using levels. For example:
Grandfather \text{Grandfather}
↓ \downarrow
Father \text{Father}
↓ \downarrow
Son \text{Son}
For siblings:
Father→{SonDaughter \text{Father} \rightarrow \begin{cases} \text{Son}\\ \text{Daughter} \end{cases}
🟡 KEY POINT
Draw a family tree when the relationship chain contains several steps. \text{Draw a family tree when the relationship chain contains several steps.}
🟢 28. SYMBOLIC BLOOD RELATIONS Some questions use symbols to represent relationships. For example:
A+B A+B
may represent:
A is the father of B A\text{ is the father of }B
If:
A−B A-B
represents:
A is the mother of B A\text{ is the mother of }B
The meaning of each symbol must be determined from the question. 🔴 IMPORTANT
Never assume the meaning of a symbol without checking the given definitions. \text{Never assume the meaning of a symbol without checking the given definitions.}
🟢 29. STATEMENT-BASED BLOOD RELATIONS In statement-based questions, convert each sentence into a relationship. For example:
A is the brother of B A\text{ is the brother of }B
means:
A↔B A\leftrightarrow B
with A being male. If:
B is the mother of C B\text{ is the mother of }C
then:
B→C B\rightarrow C
Therefore, A is the maternal uncle of C. 🟢 30. RELATIONSHIP THROUGH TWO PEOPLE If:
A is the brother of B A\text{ is the brother of }B
and:
B is the mother of C B\text{ is the mother of }C
then:
A→B→C A\rightarrow B\rightarrow C
Therefore:
A=Maternal Uncle of C A=\text{Maternal Uncle of }C
🟢 31. RELATIONSHIP THROUGH THREE PEOPLE If:
A is the father of B A\text{ is the father of }B
B is the sister of C B\text{ is the sister of }C
then A is also the father of C, assuming B and C are siblings. Therefore:
A=Father of C A=\text{Father of }C
🟢 32. HUSBAND AND WIFE RELATIONSHIP A husband and wife are spouses.
Husband↔Wife \text{Husband}\leftrightarrow\text{Wife}
They belong to the same generation.
Generation Difference=0 \text{Generation Difference}=0
🟡 KEY POINT
Marriage relationships are not blood relationships, but they may be included in family-relation questions. \text{Marriage relationships are not blood relationships, but they may be included in family-relation questions.}
🟢 33. FATHER-IN-LAW The father of one's husband or wife is:
Father-in-law \text{Father-in-law}
Therefore:
Father-in-law=Father of Spouse \text{Father-in-law} = \text{Father of Spouse}
🟢 34. MOTHER-IN-LAW The mother of one's husband or wife is:
Mother-in-law \text{Mother-in-law}
Therefore:
Mother-in-law=Mother of Spouse \text{Mother-in-law} = \text{Mother of Spouse}
🟢 35. SON-IN-LAW The husband of one's daughter is:
Son-in-law=Husband of Daughter \text{Son-in-law} = \text{Husband of Daughter}
🟢 36. DAUGHTER-IN-LAW The wife of one's son is:
Daughter-in-law=Wife of Son \text{Daughter-in-law} = \text{Wife of Son}
🟢 37. SIBLING-IN-LAW The sibling of one's spouse is commonly called a brother-in-law or sister-in-law depending on gender.
Brother-in-law=Male sibling of Spouse \text{Brother-in-law} = \text{Male sibling of Spouse}
Sister-in-law=Female sibling of Spouse \text{Sister-in-law} = \text{Female sibling of Spouse}
🟢 38. HOW TO SOLVE BLOOD RELATION QUESTIONS First identify the person whose relationship is being asked.
Step 1: Identify the starting person \text{Step 1: Identify the starting person}
Then trace each relationship.
Step 2: Follow the relationship chain \text{Step 2: Follow the relationship chain}
Draw the family tree if necessary.
Step 3: Create a simple family tree \text{Step 3: Create a simple family tree}
Determine the generation.
Step 4: Identify the generation level \text{Step 4: Identify the generation level}
Finally, identify the exact relationship.
Step 5: Determine the final relationship \text{Step 5: Determine the final relationship}
🟡 KEY POINT
Never jump directly to the answer when several relationships are given. \text{Never jump directly to the answer when several relationships are given.}
🟢 39. QUICK RELATIONSHIP CHAIN Father's brother:
Father→Brother=Uncle \text{Father}\rightarrow\text{Brother} = \text{Uncle}
Mother's sister:
Mother→Sister=Aunt \text{Mother}\rightarrow\text{Sister} = \text{Aunt}
Brother's son:
Brother→Son=Nephew \text{Brother}\rightarrow\text{Son} = \text{Nephew}
Sister's daughter:
Sister→Daughter=Niece \text{Sister}\rightarrow\text{Daughter} = \text{Niece}
Father's father:
Father→Father=Grandfather \text{Father}\rightarrow\text{Father} = \text{Grandfather}
Mother's mother:
Mother→Mother=Grandmother \text{Mother}\rightarrow\text{Mother} = \text{Grandmother}
🟡 IMPORTANT KEY POINTS
Father’s brother=Uncle \text{Father's brother}=Uncle
Father’s sister=Aunt \text{Father's sister}=Aunt
Mother’s brother=Maternal Uncle \text{Mother's brother}=Maternal\ Uncle
Mother’s sister=Maternal Aunt \text{Mother's sister}=Maternal\ Aunt
Father’s father=Paternal Grandfather \text{Father's father}=Paternal\ Grandfather
Father’s mother=Paternal Grandmother \text{Father's mother}=Paternal\ Grandmother
Mother’s father=Maternal Grandfather \text{Mother's father}=Maternal\ Grandfather
Mother’s mother=Maternal Grandmother \text{Mother's mother}=Maternal\ Grandmother
Brother’s son=Nephew \text{Brother's son}=Nephew
Brother’s daughter=Niece \text{Brother's daughter}=Niece
Sister’s son=Nephew \text{Sister's son}=Nephew
Sister’s daughter=Niece \text{Sister's daughter}=Niece
Son’s son=Grandson \text{Son's son}=Grandson
Son’s daughter=Granddaughter \text{Son's daughter}=Granddaughter
Daughter’s son=Grandson \text{Daughter's son}=Grandson
Daughter’s daughter=Granddaughter \text{Daughter's daughter}=Granddaughter
Parent=+1 generation \text{Parent}=+1\text{ generation}
Grandparent=+2 generations \text{Grandparent}=+2\text{ generations}
Child=−1 generation \text{Child}=-1\text{ generation}
Grandchild=−2 generations \text{Grandchild}=-2\text{ generations}
Sibling=0 generation difference \text{Sibling}=0\text{ generation difference}
Always trace the relationship step by step. \text{Always trace the relationship step by step.}
Draw a family tree when the relationship chain is complicated. \text{Draw a family tree when the relationship chain is complicated.}

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Logical Reasoning · Data Arrangements and Blood Relations

Data Arrangements - Formulas, Key Points and formulas

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 DATA ARRANGEMENTS\text{ DATA ARRANGEMENTS}
🟢 1. BASIC DATA ARRANGEMENT Data arrangement questions require arranging given information according to specific conditions.
Data Arrangement=Organizing given information according to the conditions \text{Data Arrangement} = \text{Organizing given information according to the conditions}
The information may involve:
Persons, Objects, Places, Numbers, Days, Ranks or Positions \text{Persons, Objects, Places, Numbers, Days, Ranks or Positions}
🟡 KEY POINT
Read all the conditions carefully before starting the arrangement. \text{Read all the conditions carefully before starting the arrangement.}
🟢 2. LINEAR ARRANGEMENT In a linear arrangement, people or objects are arranged in a straight line. For example:
ABCDE A\quad B\quad C\quad D\quad E
If AA is to the left of BB:
AB A\quad B
If AA is immediately to the right of BB:
BA B\quad A
🟡 KEY POINT
Left and right depend on the direction specified in the question. \text{Left and right depend on the direction specified in the question.}
🟢 3. POSITION IN A LINE If a person is at position PP from the left in a row of NN persons, the position from the right is:
Position from Right=N−P+1 \text{Position from Right} = N-P+1
Similarly:
Position from Left=N−P+1 \text{Position from Left} = N-P+1
if the position from the right is known. 🟡 KEY POINT
Position from opposite side=Total Persons−Known Position+1 \text{Position from opposite side} = \text{Total Persons}-\text{Known Position}+1
🟢 4. NUMBER OF PERSONS BETWEEN TWO POSITIONS If two persons occupy positions P1P_1 and P2P_2:
Persons Between=∣P1−P2∣−1 \text{Persons Between} = |P_1-P_2|-1
For example, if two persons are at positions 4 and 9:
∣9−4∣−1 |9-4|-1
=5−1 =5-1
=4 =4
🟡 KEY POINT
Always subtract 1 when finding the number of persons between two positions. \text{Always subtract 1 when finding the number of persons between two positions.}
🟢 5. IMMEDIATE LEFT AND RIGHT If AA is immediately left of BB:
AB A\quad B
If AA is immediately right of BB:
BA B\quad A
The word "immediately" means there is no person or object between them. 🟡 KEY POINT
Immediate left/right means adjacent positions. \text{Immediate left/right means adjacent positions.}
🟢 6. SECOND TO THE LEFT OR RIGHT If AA is second to the left of BB, exactly one position lies between them.
AXB A\quad X\quad B
If AA is second to the right of BB:
BXA B\quad X\quad A
🟡 KEY POINT
Second position means one person or object lies between them. \text{Second position means one person or object lies between them.}
🟢 7. THIRD POSITION If AA is third to the left of BB:
AXXB A\quad X\quad X\quad B
There are two positions between them. Therefore:
Persons Between=3−1 \text{Persons Between}=3-1
=2 =2
🟢 8. ORDER AND RANKING Ranking questions involve the position of a person or object according to a particular order. If a person ranks PP from the top in a group of NN persons:
Rank from Bottom=N−P+1 \text{Rank from Bottom} = N-P+1
If a person ranks PP from the bottom:
Rank from Top=N−P+1 \text{Rank from Top} = N-P+1
🟡 KEY POINT
Opposite Rank=Total Number−Known Rank+1 \text{Opposite Rank} = \text{Total Number}-\text{Known Rank}+1
🟢 9. TOTAL NUMBER FROM TWO RANKS If a person's rank from the top is PP and from the bottom is QQ:
Total Persons=P+Q−1 \text{Total Persons} = P+Q-1
The subtraction of 1 is necessary because the same person is counted in both ranks. 🟡 KEY POINT
Total=Top Rank+Bottom Rank−1 \text{Total}= \text{Top Rank}+\text{Bottom Rank}-1
🟢 10. CIRCULAR ARRANGEMENT In a circular arrangement, people or objects are arranged around a circle. For example:
ABCD A\quad B\quad C\quad D
may be arranged around a circle. In circular arrangements, relative positions are more important than absolute positions. 🟡 KEY POINT
There is no fixed leftmost or rightmost position in a circle. \text{There is no fixed leftmost or rightmost position in a circle.}
🟢 11. CLOCKWISE AND ANTICLOCKWISE Clockwise means moving in the same direction as the hands of a clock.
Clockwise=Direction of clock hands \text{Clockwise} = \text{Direction of clock hands}
Anticlockwise means moving in the opposite direction.
Anticlockwise=Opposite direction to clock hands \text{Anticlockwise} = \text{Opposite direction to clock hands}
🟡 KEY POINT
Always identify the facing direction before deciding left and right. \text{Always identify the facing direction before deciding left and right.}
🟢 12. FACING THE CENTRE When people face the centre of a circle:
Left and Right are determined from the person’s own perspective. \text{Left and Right are determined from the person's own perspective.}
For a person facing the centre:
Left side=Clockwise direction \text{Left side} = \text{Clockwise direction}
Right side=Anticlockwise direction \text{Right side} = \text{Anticlockwise direction}
🟡 KEY POINT
For people facing the centre, left is clockwise and right is anticlockwise. \text{For people facing the centre, left is clockwise and right is anticlockwise.}
🟢 13. FACING OUTSIDE When people face away from the centre:
Left side=Anticlockwise direction \text{Left side} = \text{Anticlockwise direction}
Right side=Clockwise direction \text{Right side} = \text{Clockwise direction}
🟡 KEY POINT
For people facing outside, left and right are reversed. \text{For people facing outside, left and right are reversed.}
🟢 14. FIXED POSITION A condition may directly specify a person's position. For example:
A is at the extreme left. A\text{ is at the extreme left.}
Then:
A____ A\quad \_\quad \_\quad \_\quad \_
If BB is at the extreme right:
A___B A\quad \_\quad \_\quad \_\quad B
🟡 KEY POINT
Place fixed positions first. \text{Place fixed positions first.}
🟢 15. BETWEEN TWO PERSONS If AA is between BB and CC:
BAC B\quad A\quad C
or:
CAB C\quad A\quad B
The exact order depends on additional conditions. 🟡 KEY POINT
"Between" does not always mean immediately between. \text{"Between"}\text{ does not always mean immediately between.}
🟢 16. ADJACENT POSITIONS Two people are adjacent when they occupy consecutive positions.
AB A\quad B
There is no person between them. Therefore:
Number of Persons Between=0 \text{Number of Persons Between}=0
🟢 17. NOT ADJACENT If two persons are not adjacent:
AXB A\quad X\quad B
At least one person or object must be between them.
Persons Between≥1 \text{Persons Between}\geq1
🟢 18. ORDERING BY AGE, HEIGHT OR WEIGHT Data arrangement can involve ordering people according to measurable characteristics. For increasing order:
A<B<C<D A<B<C<D
For decreasing order:
D>C>B>A D>C>B>A
🟡 KEY POINT
Convert every comparison into a clear order before solving. \text{Convert every comparison into a clear order before solving.}
🟢 19. COMPARISON STATEMENTS If AA is taller than BB:
A>B A>B
If CC is shorter than AA:
C<A C<A
Therefore:
A>C A>C
If:
A>B>C A>B>C
then:
A>B A>B
B>C B>C
and:
A>C A>C
🟢 20. CONDITIONAL ARRANGEMENT Some questions contain conditions such as:
A sits to the left of B. A\text{ sits to the left of }B.
C sits immediately right of D. C\text{ sits immediately right of }D.
E is not at an extreme position. E\text{ is not at an extreme position.}
All conditions must be satisfied simultaneously. 🟡 KEY POINT
Do not solve each condition separately without checking the complete arrangement. \text{Do not solve each condition separately without checking the complete arrangement.}
🟢 21. GROUPING ARRANGEMENT Some questions require placing people or objects into groups. For example:
Group 1: A,B,C \text{Group 1}:\ A,B,C
Group 2: D,E,F \text{Group 2}:\ D,E,F
If AA and BB must be together:
(A,B) (A,B)
can be treated as one unit during the initial arrangement. 🟡 KEY POINT
Combine items that must stay together into a block. \text{Combine items that must stay together into a block.}
🟢 22. DAYS AND SCHEDULE ARRANGEMENT Data arrangement may involve assigning activities to different days. For example:
Monday→A \text{Monday}\rightarrow A
Tuesday→B \text{Tuesday}\rightarrow B
Wednesday→C \text{Wednesday}\rightarrow C
Conditions may specify before, after, immediately before or immediately after. 🟡 KEY POINT
Before and after conditions should be converted into positional relationships. \text{Before and after conditions should be converted into positional relationships.}
🟢 23. BEFORE AND AFTER If AA occurs before BB:
A<B A<B
If CC occurs after BB:
B<C B<C
Therefore:
A<B<C A<B<C
🟡 KEY POINT
Before/after relationships help create an order chain. \text{Before/after relationships help create an order chain.}
🟢 24. IMMEDIATELY BEFORE AND AFTER If AA occurs immediately before BB:
AB A\quad B
If CC occurs immediately after DD:
DC D\quad C
🟡 KEY POINT
"Immediately before/after" means consecutive positions. \text{"Immediately before/after"}\text{ means consecutive positions.}
🟢 25. EXTREME POSITIONS In a row, the extreme positions are:
First Position and Last Position \text{First Position and Last Position}
For NN positions:
First Position=1 \text{First Position}=1
Last Position=N \text{Last Position}=N
🟡 KEY POINT
Check extreme positions before filling middle positions. \text{Check extreme positions before filling middle positions.}
🟢 26. MIDDLE POSITION If there are NN positions and NN is odd, the middle position is:
Middle Position=N+12 \text{Middle Position} = \frac{N+1}{2}
For example, for 9 positions:
9+12=5 \frac{9+1}{2}=5
Therefore:
Middle Position=5 \text{Middle Position}=5
🟢 27. TWO MIDDLE POSITIONS If the number of positions is even, there are two middle positions. For NN positions:
Middle Positions=N2andN2+1 \text{Middle Positions} = \frac{N}{2} \quad\text{and}\quad \frac{N}{2}+1
For 10 positions:
102=5 \frac{10}{2}=5
and:
5+1=6 5+1=6
Therefore:
Middle Positions=5 and 6 \text{Middle Positions}=5\text{ and }6
🟢 28. POSITION FROM BOTH ENDS If there are NN people and a person is at position PP from the left:
Position from Right=N−P+1 \text{Position from Right} = N-P+1
If the position from the right is QQ:
Position from Left=N−Q+1 \text{Position from Left} = N-Q+1
🟢 29. NUMBER OF PEOPLE BETWEEN TWO PEOPLE If two people are at positions PP and QQ:
Number Between=∣P−Q∣−1 \text{Number Between} = |P-Q|-1
If they are at positions 3 and 8:
∣8−3∣−1 |8-3|-1
=4 =4
Therefore:
Number Between=4 \text{Number Between}=4
🟢 30. BEST METHOD TO SOLVE DATA ARRANGEMENT First identify the type of arrangement.
Linear \text{Linear}
Circular \text{Circular}
Ranking \text{Ranking}
Grouping \text{Grouping}
Scheduling \text{Scheduling}
Then:
Step 1: Identify fixed information \text{Step 1: Identify fixed information}
Step 2: Place definite positions \text{Step 2: Place definite positions}
Step 3: Create blocks for linked information \text{Step 3: Create blocks for linked information}
Step 4: Apply remaining conditions \text{Step 4: Apply remaining conditions}
Step 5: Check every condition \text{Step 5: Check every condition}
Step 6: Answer the question \text{Step 6: Answer the question}
🟡 IMPORTANT KEY POINTS
Read every condition carefully. \text{Read every condition carefully.}
Place fixed positions first. \text{Place fixed positions first.}
Use blocks for people who must be together. \text{Use blocks for people who must be together.}
Use position numbers to avoid confusion. \text{Use position numbers to avoid confusion.}
For opposite rank, use N−P+1. \text{For opposite rank, use }N-P+1.
For people between two positions, use ∣P−Q∣−1. \text{For people between two positions, use }|P-Q|-1.
For circular arrangements, identify the facing direction first. \text{For circular arrangements, identify the facing direction first.}
For centre-facing people, left is clockwise and right is anticlockwise. \text{For centre-facing people, left is clockwise and right is anticlockwise.}
For outside-facing people, left is anticlockwise and right is clockwise. \text{For outside-facing people, left is anticlockwise and right is clockwise.}
Always verify the complete arrangement before selecting the answer. \text{Always verify the complete arrangement before selecting the answer.}

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Logical Reasoning · Clocks _ Calenders

Basics- Formulas, Key Points and Examples

🔵 CLOCKS AND CALENDARS 🟢 1. BASIC CLOCK CONCEPT A clock has 12 numbers and completes one full revolution in 12 hours.

360∘=12 hours 360^\circ=12\text{ hours}
The minute hand completes one revolution in 60 minutes.
360∘=60 minutes 360^\circ=60\text{ minutes}
Therefore:
1 minute=6∘ 1\text{ minute}=6^\circ
The hour hand moves 30° in one hour.
1 hour=30∘ 1\text{ hour}=30^\circ
The hour hand moves 0.5° in one minute.
1 minute=0.5∘ 1\text{ minute}=0.5^\circ
🟡 KEY POINT
Minute Hand Speed=6∘ per minute \text{Minute Hand Speed}=6^\circ\text{ per minute}
Hour Hand Speed=0.5∘ per minute \text{Hour Hand Speed}=0.5^\circ\text{ per minute}
🟢 2. MOVEMENT OF MINUTE HAND The minute hand moves 6° every minute.
Angle moved by Minute Hand=6M \text{Angle moved by Minute Hand} = 6M
where MM is the number of minutes. For example, in 20 minutes:
6×20=120∘ 6\times20=120^\circ
🟡 KEY POINT
Minute Hand Angle=6M \text{Minute Hand Angle}=6M
🟢 3. MOVEMENT OF HOUR HAND The hour hand moves 30° in one hour.
Angle moved in 1 hour=30∘ \text{Angle moved in 1 hour}=30^\circ
Since one hour contains 60 minutes:
Angle moved in 1 minute=3060 \text{Angle moved in 1 minute} = \frac{30}{60}
=0.5∘ =0.5^\circ
Therefore, at HH hours and MM minutes:
Hour Hand Angle=30H+0.5M \text{Hour Hand Angle} = 30H+0.5M
🟢 4. ANGLE BETWEEN THE HANDS OF A CLOCK At HH hours and MM minutes:
Hour Hand Angle=30H+0.5M \text{Hour Hand Angle} = 30H+0.5M
Minute Hand Angle=6M \text{Minute Hand Angle} = 6M
Therefore:
Angle=∣30H+0.5M−6M∣ \text{Angle} = \left| 30H+0.5M-6M \right|
Simplifying:
Angle=∣30H−5.5M∣ \text{Angle} = |30H-5.5M|
The smaller angle between the hands is:
Smaller Angle=min⁡(∣30H−5.5M∣,360−∣30H−5.5M∣) \text{Smaller Angle} = \min \left( |30H-5.5M|, 360-|30H-5.5M| \right)
🔴 IMPORTANT
If the calculated angle is greater than 180∘, subtract it from 360∘. \text{If the calculated angle is greater than }180^\circ, \text{ subtract it from }360^\circ.
Smaller Angle=360∘−Larger Angle \text{Smaller Angle} = 360^\circ-\text{Larger Angle}
🟢 5. RIGHT ANGLE BETWEEN CLOCK HANDS A right angle is:
90∘ 90^\circ
Therefore, the clock hands are perpendicular when:
∣30H−5.5M∣=90 |30H-5.5M|=90
🟡 KEY POINT
Right Angle=90∘ \text{Right Angle}=90^\circ
🟢 6. STRAIGHT ANGLE BETWEEN CLOCK HANDS A straight angle is:
180∘ 180^\circ
Therefore, the clock hands are opposite when:
∣30H−5.5M∣=180 |30H-5.5M|=180
🟡 KEY POINT
Straight Angle=180∘ \text{Straight Angle}=180^\circ
🟢 7. COINCIDENCE OF CLOCK HANDS The hands coincide when both hands are at the same position. Therefore:
30H+0.5M=6M 30H+0.5M=6M
Simplifying:
30H=5.5M 30H=5.5M
Therefore:
M=30H5.5 M=\frac{30H}{5.5}
M=60H11 M=\frac{60H}{11}
The hands coincide approximately every:
72011 minutes \frac{720}{11}\text{ minutes}
Therefore:
72011=65511 minutes \frac{720}{11} = 65\frac{5}{11}\text{ minutes}
🔴 IMPORTANT
The hour and minute hands coincide 11 times in 12 hours. \text{The hour and minute hands coincide 11 times in 12 hours.}
🟢 8. OPPOSITE POSITIONS OF CLOCK HANDS The hands are opposite when the angle between them is:
180∘ 180^\circ
Therefore:
∣30H−5.5M∣=180 |30H-5.5M|=180
🟢 9. CLOCK HANDS AT A GIVEN ANGLE If the angle between the hands is θ\theta:
∣30H−5.5M∣=θ |30H-5.5M|=\theta
For a 60∘60^\circ angle:
∣30H−5.5M∣=60 |30H-5.5M|=60
For a 120∘120^\circ angle:
∣30H−5.5M∣=120 |30H-5.5M|=120
For a 90∘90^\circ angle:
∣30H−5.5M∣=90 |30H-5.5M|=90
🟢 10. ANGLE MOVED BY THE MINUTE HAND The minute hand completes:
360∘ 360^\circ
in 60 minutes. Therefore:
Angle per minute=36060 \text{Angle per minute} = \frac{360}{60}
=6∘ =6^\circ
Hence:
Angle in M minutes=6M \text{Angle in }M\text{ minutes} = 6M
🟢 11. ANGLE MOVED BY THE HOUR HAND The hour hand completes:
360∘ 360^\circ
in 12 hours. Therefore:
Angle per hour=36012 \text{Angle per hour} = \frac{360}{12}
=30∘ =30^\circ
Since one hour contains 60 minutes:
Angle per minute=3060 \text{Angle per minute} = \frac{30}{60}
=0.5∘ =0.5^\circ
🟢 12. CLOCK GAINING TIME If a clock gains time, it moves faster than the correct clock.
Gain per hour=Total GainTotal Time in Hours \text{Gain per hour} = \frac{\text{Total Gain}}{\text{Total Time in Hours}}
🟡 KEY POINT
A fast clock shows more time than the actual time. \text{A fast clock shows more time than the actual time.}
🟢 13. CLOCK LOSING TIME If a clock loses time, it moves slower than the correct clock.
Loss per hour=Total LossTotal Time in Hours \text{Loss per hour} = \frac{\text{Total Loss}}{\text{Total Time in Hours}}
🟡 KEY POINT
A slow clock shows less time than the actual time. \text{A slow clock shows less time than the actual time.}
🟢 14. RELATIVE GAIN AND LOSS OF CLOCKS If one clock gains time and another clock loses time, their relative difference increases.
Relative Difference=Gain of First Clock+Loss of Second Clock \text{Relative Difference} = \text{Gain of First Clock} + \text{Loss of Second Clock}
If both clocks gain or both clocks lose time:
Relative Difference=∣Rate of First Clock−Rate of Second Clock∣ \text{Relative Difference} = \left| \text{Rate of First Clock} - \text{Rate of Second Clock} \right|
🟡 KEY POINT
Always compare the rates of the two clocks when solving relative clock problems. \text{Always compare the rates of the two clocks when solving relative clock problems.}
🟢 15. BASIC CALENDAR CONCEPT A calendar is based on days, weeks, months and years. One week contains:
7 days 7\text{ days}
A normal year contains:
365 days 365\text{ days}
A leap year contains:
366 days 366\text{ days}
🟢 16. ODD DAYS Odd days are the number of days left after complete weeks are removed. Since:
1 week=7 days 1\text{ week}=7\text{ days}
The number of odd days is the remainder when the number of days is divided by 7. For 365 days:
365=52×7+1 365=52\times7+1
Therefore:
Odd Days=1 \text{Odd Days}=1
For 366 days:
366=52×7+2 366=52\times7+2
Therefore:
Odd Days=2 \text{Odd Days}=2
🟢 17. NORMAL YEAR A normal year has:
365 days 365\text{ days}
Therefore:
365=52×7+1 365=52\times7+1
Hence:
Normal Year=1 Odd Day \text{Normal Year}=1\text{ Odd Day}
🟢 18. LEAP YEAR A leap year has:
366 days 366\text{ days}
Therefore:
366=52×7+2 366=52\times7+2
Hence:
Leap Year=2 Odd Days \text{Leap Year}=2\text{ Odd Days}
🟢 19. LEAP YEAR RULE A year is generally a leap year if it is divisible by 4. For example:
2024÷4=506 2024\div4=506
Therefore:
2024 is a leap year. 2024\text{ is a leap year.}
However, century years must also be divisible by 400. For example:
2000÷400=5 2000\div400=5
Therefore:
2000 is a leap year. 2000\text{ is a leap year.}
But:
1900÷400=4.75 1900\div400=4.75
Therefore:
1900 is not a leap year. 1900\text{ is not a leap year.}
🔴 IMPORTANT
A century year is a leap year only if it is divisible by 400. \text{A century year is a leap year only if it is divisible by 400.}
🟢 20. DAYS IN DIFFERENT MONTHS The number of days in each month is:
January=31 \text{January}=31
February=28 \text{February}=28
March=31 \text{March}=31
April=30 \text{April}=30
May=31 \text{May}=31
June=30 \text{June}=30
July=31 \text{July}=31
August=31 \text{August}=31
September=30 \text{September}=30
October=31 \text{October}=31
November=30 \text{November}=30
December=31 \text{December}=31
In a leap year:
February=29 \text{February}=29
🟢 21. DAYS IN A WEEK The seven days of the week are:
Sunday \text{Sunday}
Monday \text{Monday}
Tuesday \text{Tuesday}
Wednesday \text{Wednesday}
Thursday \text{Thursday}
Friday \text{Friday}
Saturday \text{Saturday}
🟡 KEY POINT
1 week=7 days 1\text{ week}=7\text{ days}
🟢 22. DAY AFTER A GIVEN NUMBER OF DAYS If today is a particular day, the day after NN days depends on the remainder when NN is divided by 7.
N=7q+r N=7q+r
where rr is the number of odd days. Therefore:
Required Day=Starting Day+r \text{Required Day} = \text{Starting Day}+r
🟡 KEY POINT
For calendar problems, divide the number of days by 7 and use the remainder. \text{For calendar problems, divide the number of days by 7 and use the remainder.}
🟢 23. DAY BEFORE A GIVEN NUMBER OF DAYS If we need to find the day before a given date, subtract the odd days.
N=7q+r N=7q+r
Therefore:
Required Day=Starting Day−r \text{Required Day} = \text{Starting Day}-r
🟢 24. DAY OF THE WEEK To determine the day of the week for a particular date, calculate the total number of odd days from a known reference date. The calculation generally involves:
Odd Days=Odd Days in Complete Years+Odd Days in Complete Months+Odd Days in Remaining Days \text{Odd Days} = \text{Odd Days in Complete Years} + \text{Odd Days in Complete Months} + \text{Odd Days in Remaining Days}
Then:
Required Day=Reference Day+Total Odd Days \text{Required Day} = \text{Reference Day}+\text{Total Odd Days}
The final result is reduced using:
Total Odd Days mod 7 \text{Total Odd Days}\bmod7
🟢 25. ODD DAYS IN COMPLETE YEARS For a group of years:
Total Days=365(Number of Normal Years)+366(Number of Leap Years) \text{Total Days} = 365(\text{Number of Normal Years}) + 366(\text{Number of Leap Years})
Then:
Odd Days=Total Days mod 7 \text{Odd Days} = \text{Total Days}\bmod7
🟢 26. ODD DAYS IN COMPLETE MONTHS The number of days in complete months is added before the required date. For a normal year:
Days in February=28 \text{Days in February}=28
For a leap year:
Days in February=29 \text{Days in February}=29
Then:
Odd Days=Total Days mod 7 \text{Odd Days} = \text{Total Days}\bmod7
🟢 27. NUMBER OF ODD DAYS BETWEEN TWO DATES To find the number of days between two dates:
Total Days=Days in Complete Years+Days in Complete Months+Remaining Days \text{Total Days} = \text{Days in Complete Years} + \text{Days in Complete Months} + \text{Remaining Days}
Then:
Odd Days=Total Days mod 7 \text{Odd Days} = \text{Total Days}\bmod7
🟢 28. SAME CALENDAR YEAR Two years can have the same calendar when their starting day is the same and the total odd days between them is a multiple of 7.
Total Odd Days≡0(mod7) \text{Total Odd Days}\equiv0\pmod7
Therefore:
Starting Day of Year 1=Starting Day of Year 2 \text{Starting Day of Year 1} = \text{Starting Day of Year 2}
🟡 KEY POINT
Leap years affect the starting day of the following year. \text{Leap years affect the starting day of the following year.}
🟢 29. CALENDAR AFTER A NORMAL YEAR A normal year has one odd day. Therefore, if a normal year starts on a particular day:
Next Year Start=Starting Day+1 \text{Next Year Start} = \text{Starting Day}+1
For example, if a normal year starts on Monday:
Next Year Start=Tuesday \text{Next Year Start}=Tuesday
🟢 30. CALENDAR AFTER A LEAP YEAR A leap year has two odd days. Therefore:
Next Year Start=Starting Day+2 \text{Next Year Start} = \text{Starting Day}+2
For example, if a leap year starts on Monday:
Next Year Start=Wednesday \text{Next Year Start}=Wednesday
🟢 31. IMPORTANT CLOCK FORMULAS FOR REVISION Minute hand angle:
Minute Hand Angle=6M \text{Minute Hand Angle}=6M
Hour hand angle:
Hour Hand Angle=30H+0.5M \text{Hour Hand Angle}=30H+0.5M
Angle between hands:
Angle=∣30H−5.5M∣ \text{Angle}=|30H-5.5M|
Smaller angle:
Smaller Angle=min⁡(∣30H−5.5M∣,360−∣30H−5.5M∣) \text{Smaller Angle} = \min \left( |30H-5.5M|, 360-|30H-5.5M| \right)
Right angle:
∣30H−5.5M∣=90 |30H-5.5M|=90
Straight angle:
∣30H−5.5M∣=180 |30H-5.5M|=180
Coincidence:
M=60H11 M=\frac{60H}{11}
🟢 32. IMPORTANT CALENDAR FORMULAS FOR REVISION Number of days in a normal year:
365=52×7+1 365=52\times7+1
Therefore:
Normal Year=1 Odd Day \text{Normal Year}=1\text{ Odd Day}
Number of days in a leap year:
366=52×7+2 366=52\times7+2
Therefore:
Leap Year=2 Odd Days \text{Leap Year}=2\text{ Odd Days}
Odd days:
Odd Days=Number of Days mod 7 \text{Odd Days} = \text{Number of Days}\bmod7
Day after NN days:
N=7q+r N=7q+r
Required Day=Starting Day+r \text{Required Day} = \text{Starting Day}+r
Day before NN days:
N=7q+r N=7q+r
Required Day=Starting Day−r \text{Required Day} = \text{Starting Day}-r
🟡 KEY POINTS
1 hour=60 minutes 1\text{ hour}=60\text{ minutes}
1 minute=60 seconds 1\text{ minute}=60\text{ seconds}
1 week=7 days 1\text{ week}=7\text{ days}
1 normal year=365 days 1\text{ normal year}=365\text{ days}
1 leap year=366 days 1\text{ leap year}=366\text{ days}
1 normal year=1 odd day 1\text{ normal year}=1\text{ odd day}
1 leap year=2 odd days 1\text{ leap year}=2\text{ odd days}
Minute hand moves 6∘ per minute. \text{Minute hand moves }6^\circ\text{ per minute.}
Hour hand moves 0.5∘ per minute. \text{Hour hand moves }0.5^\circ\text{ per minute.}
Use ∣30H−5.5M∣ to calculate the angle between clock hands. \text{Use }|30H-5.5M|\text{ to calculate the angle between clock hands.}
For calendar problems, reduce the number of days using division by 7. \text{For calendar problems, reduce the number of days using division by 7.}
A leap year is divisible by 4, except century years. \text{A leap year is divisible by 4, except century years.}
A century year is a leap year only when it is divisible by 400. \text{A century year is a leap year only when it is divisible by 400.}
Always check whether February has 28 or 29 days. \text{Always check whether February has 28 or 29 days.}

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